用GameLoop模拟器在電腦上玩Linux News: Open Source & Tech

Linux News: Open Source & Tech 電腦版

來自發行商 Pinenuts Android Developers 的 Linux News: Open Source & Tech 能夠在安卓系統上運行。

現在，您可以在電腦上使用 GameLoop 模擬器流暢地玩 Linux News: Open Source & Tech。

在 GameLoop 遊戲庫或搜索結果中下載。 不需要再暢玩遊戲時盯著電池電量或被令人懊惱的來電打斷。

只需在電腦大屏幕上免費下載暢玩Linux News: Open Source & Tech 電腦版！

Linux News: Open Source & Tech 簡介

All the Latest News on Linux and Open Source, HowTo and Tutorials! A fast, simple and immediate mobile news feed reader for Linux News!

Choose and read the most famous Linux News blogs and sites with your mobile free of charge and in the fastest way possible.

If you want to stay up to date with what happens in the Linux, Unix and Open Source World and use as little time as possible, then this app is what you need!

Linux News is a RSS Feed Reader but unlike other excellent news readers, it will bring you directly to the headlines without wasting any time messing around with the user interface or news loading. Linux News is the best app for the daily reader.

You will find all the latest News, software releases, security issues and fixes, Howto and tutorials.

You can reorder and disable the feeds that you are not interested in.

Linux News will show you the content of these news sites:

* SlashDot Linux

* LWN.net (Linux Weekly News)

* LXer

* Linux.com

* Linux Magazine

* Linux Insider

* TuxMachines

* Phoronix

* OS News

* OSTechNix

* Linux Today

* Linux Reddit channel

* Opensource Reddit channel

* OMGUbuntu (Ubuntu news)

* NoobsLab

* Planet Ubuntu

* UbuntuFree

* Opensource.com

* Ghacks

* LinuxSecurity.com

* LinuxGizmos.com

* GamingOnLinux

* TecMint

* DistroWatch

* HowtoForge.com

* Itsfoss.net

and more.

If you want another site to be included in the list, please send us an email.

We also appreciate critics and suggestions!

Disclaimer: This app is not affiliated nor related with any of the blogs and sites cited here. The content the app shows comes from publicly available rss feeds and thus the app is not to be held responsible for any of the content displayed.